2NaOH+ FeCl₂ -- 2NaCl + Fe(OH)2 If 13.5 g of sodium hydroxide reacts with an excess of iron (II) chloride according to the

Question

2NaOH+ FeCl₂ --> 2NaCl + Fe(OH)2
If 13.5 g of sodium hydroxide reacts with an excess of iron (II) chloride according to the
equation above, how much Fe(OH)2 will be produced?
19.72 g
15.17 g
9.86 g
30.33 g

Kunduz · Accepted Answer

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2NaOH+ FeCl₂ --> 2NaCl + Fe(OH)2 If 13.5 g of sodium