Question:

2NaOH+ FeCl₂ --> 2NaCl + Fe(OH)2 If 13.5 g of sodium

Last updated: 08/09/2022

2NaOH+ FeCl₂ --> 2NaCl + Fe(OH)2 If 13.5 g of sodium

2NaOH+ FeCl₂ --> 2NaCl + Fe(OH)2 If 13.5 g of sodium hydroxide reacts with an excess of iron (II) chloride according to the equation above, how much Fe(OH)2 will be produced? 19.72 g 15.17 g 9.86 g 30.33 g