3 399 10 ms 1 1 When a potential difference of 1 5 V is

Last updated: 6/1/2023

3 399 10 ms 1 1 When a potential difference of 1 5 V is applied across a wire of length 0 2 m and area of cross section 0 3 mm a current of 2 4 A flows through the wire If the number density of free electrons in the wire is 8 4 x 1028 m 3 calculate the average relaxation time Given that mass of electron 9 1 x 10 311 electron kg and charge on 1 6 x 10 19