9 At 20 C 0 258 mol A g and 0 592 mol B g are mixed in a

Last updated: 6/30/2023

9 At 20 C 0 258 mol A g and 0 592 mol B g are mixed in a closed vessel of 5 L capacity to conduct the following reaction A g 2B g C g If 0 035 mol C g remains in the equilibrium mixture then determine the partial pressure of each constituent at equilibrium Ans According to the equation 1 mol A g reacts with 2 mol B g to produce 1 mol C g Hence 0 035 mol A g and 2 0 035 0 07 mol B g are required to produce 0 035 mol C g Therefore equilibrium molar concentrations of different constituents will be as follows No of moles at equilibrium A g 0 258 0 035 0 223 2B g 0 592 0 07 0 522 C g 0 035 0 223 Equilibrium conc mol L 0 0446 As given T 273 20 K 293 K At equilibrium PA A RT 0 0446 0 0821 293 1 072 atm PB B RT 0 1044 0 0821 293 2 511 atm Pc C RT 7 x 10 3 x 0 0821 293 0 168 0 522 5 0 1044 0 035 7 x 10 3