A 0.43-kilogram soccer ball sits on the grass. The

Last updated: 7/30/2022

A 0.43-kilogram soccer ball sits on the grass. The coefficient of static friction between the soccer ball and the grass is 0.4. A players kicks the ball horizontally, resulting in an initial acceleration of 65 m/s² horizontally. What was the force of static friction applied to the ball at the time of the kick? .4(.43) 10 1.73 f=1.72 N What was the force of the kick? F=m.a/ (43)(65m²²) = 27.950 F=27.95N Imagine the situation was on a different surface like artificial turf, and the coefficient of static friction changed to 0.45. To get the same acceleration, how much more force would the kick need?