Question:
A 52.0-mL volume of 0.35 M CH3COOH (K₁ = 1.8 x 10-5) is
Last updated: 8/5/2022
![A 52.0-mL volume of 0.35 M CH3COOH (K₁ = 1.8 x 10-5) is](https://media.kunduz.com/media/sug-question/raw/59812884-1659709808.2699327.jpeg?h=512)
A 52.0-mL volume of 0.35 M CH3COOH (K₁ = 1.8 x 10-5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of NaOH. Express your answer numerically.