Question:

A 740.0 kg boulder is raised from a quarry 115 m deep by a

Last updated: 7/30/2022

A 740.0 kg boulder is raised from a quarry 115 m deep by a

A 740.0 kg boulder is raised from a quarry 115 m deep by a long chain having a mass of 555.0 kg. This chain is of uniform strength, but at any point it can support a maximum tension no greater than 2.60 times its weight without breaking. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An air track in a physics lab. Set Up: The maximum tension in the chain is at the top of the chain. Apply F = ma to the composite object of chain and boulder. Use the constant acceleration kinematic equations to relate the acceleration to time. Let +y be upward. T = 2.60W chain mtot = mchain +mboulder = 1295 kg. Solve: EF, a = Part B = may gives T-mtotg = mtota. t = 4.92 2.60(555.0kg) 1295 kg T-mtot9 mtot − 1) (9.80 m/s²) = 1.12 m/s². μA a = 2.60 mchaing-mtotg mtot How long does it take for the boulder to be lifted out at maximum acceleration if it started from rest? Express your answer with the appropriate units. S Submit Previous Answers Request Answer ? 2.60 mchain mtot X Incorrect; Try Again; 8 attempts remaining -1) g