A ball is thrown straight up with an initial velocity of 64 feet per second from the top of a building that is 80 ft tall. The

Question

A ball is thrown straight up with an initial velocity of 64 feet per second from the top of a building that is 80 ft tall. The height of the ball t seconds after it is thrown is given by the function s(t) = -16t² +64t + 80.
a. After how many seconds will the ball reach its maximum height?
b. What is the maximum height the ball reaches? 
c. When will the ball reach the ground? In     seconds.

Kunduz · Accepted Answer

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