Question:

A dielectric slab K 4 is put between the plates of a charged

Last updated: 6/11/2023

A dielectric slab K 4 is put between the plates of a charged

A dielectric slab K 4 is put between the plates of a charged parallel plate capacitor If charge on the positive plate of the capacitor is Q then the induced charge on the face of the slab that faces the positive plate will be 1 30 4 3 3Q 2 4 S 0 4 ol