Question:

A proton (m = 1.67 × 10-27 kg) traveling at 2.50 × 105

Last updated: 7/31/2022

A proton (m = 1.67 × 10-27 kg) traveling at 2.50 × 105

A proton (m = 1.67 × 10-27 kg) traveling at 2.50 × 105 m/s collides with an unknown particle initially at rest. After the collision, the proton reverses direction and travels at 1.10 x 105 m/s. Determine the change in momentum of the unknown particle.