A student combined a 2.0 x 10-3 mol/L solution of lead

Last updated: 8/4/2022

A student combined a 2.0 x 10-3 mol/L solution of lead nitrate, Pb(NO3)2(aq), with a 1.0 x 10-3 mol/L solution of hydrochloric acid, HCl(aq), in equal volumes (so there's no need to find a final volume). Their calculations so far are shown in the image provided. Will a precipitate of lead chloride, PbC12(s), form? Support your answer by including all relevant calculations and assumptions. (6 marks) HINT: Find the trial ion quotient. *SHOW YOUR WORK! K PbCl₂ (s) Ksp = 1.6 × 10-5 * Overall equation. Pb(NO3)2(aq) + HCl(aq) = PbCl₂(s) + HNO3(aq) *used solubility table Dissociation equations. Pb(NO3)2(aq) = Pb²+(aq) + 2 NO3(aq) HCl(aq) = H+ (aq) + Cl(aq)