(a) The 2 kg wood box in the Figure above on the left slides up a vertical wood wall while you push on it at a 45° angle. The

Question

(a) The 2 kg wood box in the Figure above on the left slides up a vertical wood wall while you push on it at a 45° angle. The coefficient of kinetic friction for wood on wood is = 0.2. What magnitude force Fpush should you apply to cause the box to slide up at a constant speed? Recall that constant speed means a = 0 m/sec². Answer: 34.6 N.
(b) Let's re-do part (a), but with the box now sliding down the vertical wood wall while you push on it at a 45° angle. # is still μ = 0.2. What magnitude force Fpush should you apply to cause the box to slide down at a constant speed? Recall that constant speed means a = 0 m/sec². Answer: 23.1 N.

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