Calculate the number of milliliters of 0.697

Last updated: 8/4/2022

Calculate the number of milliliters of 0.697 M Ba(OH)₂ required to precipitate all of the Cr³+ ions in 197 mL of 0.414 M Cr₂(SO4)3 solution as Cr(OH)3. The equation for the reaction is: Cr₂(SO4)3(aq)+ 3Ba(OH)₂(aq) →→2Cr(OH)3(s) + 3BaSO4(aq) mL Ba(OH)₂