Calculate the volume of 1.87 M Nal that would be needed to precipitate all of the Hg +2 ion from 199 mL of a 1.96 M Hg(NO3)2.

Question

Calculate the volume of 1.87 M Nal that would be needed to precipitate all of the Hg +2 ion from 199 mL of a 1.96 M Hg(NO3)2. The equation for the reaction is
 2 Nal(aq) + Hg(NO3)2(aq) Hgl2( s) + 2 NaNO3(aq)

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