Consider h(x) = 16 (x² - 64)^2/3 Determine the intervals on which h is concave down. h is concave down on: h is concave down

Question

Consider h(x) = 16 (x² - 64)^2/3
Determine the intervals on which h is concave down.
h is concave down on:
h is concave down nowhere.
Determine the intervals on which h is concave up.
h is concave up on:
h is concave up nowhere.
Determine the value and location of any inflection point of h. Enter the solution in (x, h(x)) form. If multiple solutions exist, use a comma-separated list to enter the solutions.
h has an inflection point at:
h has no inflection point.

Kunduz · Accepted Answer

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