Question:

Consider sec(-(2 + 3x)) = √2. The principle solution is x =

Last updated: 8/11/2022

Consider sec(-(2 + 3x)) = √2. The principle solution is x =

Consider sec(-(2 + 3x)) = √2. The principle solution is x = We now determine all solutions for this problem. What is the period of secant? List all values of 0 in the interval [0, 2x) such that sec(0) = √2. (Notice the relationship between the period and the interval here.) (List all values in this answer box separated by a comma. Depending on the trig function and value, it is possible that there will only be one entry.) Thus, using the above work, all solutions are given by x=_ where k € Z. (There will be a separate formula for each value you listed in the previous answer box. List each formula in this answer box separated by a comma. Remember to use k as appropriate.)