Consider the following reaction: CH₂(g) +40₂(g) →CCl₂(g) +

Last updated: 7/27/2022

Consider the following reaction: CH₂(g) +40₂(g) →CCl₂(g) + 4HCl (g) What mass of CCl4 will be formed if 1.20 moles of methane react with 1.07 moles of chlorine? 41.1 g 658 g 185 g 165 g 19.0 g