Question:
Consider the following unbalanced equation: C2H6(g)+Oz(g)→
Last updated: 8/4/2022
Consider the following unbalanced equation: C2H6(g)+Oz(g)→ CO2(g)+H2O(g) Which amount requires more oxygen gas, 2.43 mol C₂H6 or 28.8 g C₂H6? HOW DO WE GET THERE? For 2.43 mol C₂H6: What is the mole ratio between C₂H6 and O₂ in the balanced equation? 2C2H6(g) + 702(g) → 4CO2(g) + 6H₂O(g) X = Y = X mol O₂ Y mol C₂H6 mol O₂ mol C₂H6