Question:

Consider the reaction: 2 HI (g) = H₂ (g) + 12 (g) Kc = 7.21

Last updated: 7/31/2022

Consider the reaction: 2 HI (g) = H₂ (g) + 12 (g) Kc = 7.21

Consider the reaction: 2 HI (g) = H₂ (g) + 12 (g) Kc = 7.21 If at equilibrium the reaction vessel contains 1.20 M of H₂ and 1.70 M 12, then what is the equilibrium concentration of HI?