Continue to go with f[x] = Log[x] So that f'[x]=1/x But this

Last updated: 8/9/2022

Continue to go with f[x] = Log[x] So that f'[x]=1/x But this time come up with a small h so that f[x+h] - f[x]/h calculates f'[x] to at least four accurate decimals for all the x 's with 0.25 ≤x≤2.5.