Core Chemistry Skill: Calculating the Molar Solubility The

Last updated: 8/5/2022

Core Chemistry Skill: Calculating the Molar Solubility The solubility of a substance is the quantity that dissolves to form a saturated solution, and it can be represented by the solubility product expression ( Ksp). The solubility product expression is equivalent to the product of the ion concentrations after each is raised to a power that is equal to its coefficient in the balanced equilibrium equation. For an example, see the following reaction involving calcium phosphate and its corresponding solubility product expression: Ca3(PO4)2 (s) = 3Ca²+ (aq) + 2PO4³- (aq) Ksp = [Ca²+1³ [PO4³-1² The molar solubility (S) of a slightly soluble salt is the number of moles of solute that dissolve in 1 L of solution and has the units M. For the example above, every 1 mol of solute that dissolves produces 3 mol of Ca²+ and 2 mol of PO4³ , so the molar solubility is equivalent to S= [Ca²+] 3 (PO₁3-1 2 Part A O MgCrO4 O CrO4²- D Mg2+ If MgCrO4 were added to water to form 1 L of solution, the concentration of which species will be equal to the molar solubility? Check all that apply. ►'View Available Hint(s) Submit Part B Complete previous part(s) 14 of 17 Part C. Complete previous part(s) Review | Constants | Periodic Table