Question:

D F AG 16 kJ mol and K equilibrium constant 500 You add 10

Last updated: 6/15/2023

D F AG 16 kJ mol and K equilibrium constant 500 You add 10

D F AG 16 kJ mol and K equilibrium constant 500 You add 10 000 moles of F to a test tube and let the reaction run undisturbed When it finally hits equilibrium you will have 20 moles of D and 9 980 moles of F 9 980 moles of D and 20 moles of F O moles of D and 10 000 moles of F 500 moles of each