Question:

Determine the resulting pH when 0.040 mol of solid NaOH is

Last updated: 7/23/2022

Determine the resulting pH when 0.040 mol of solid NaOH is

Determine the resulting pH when 0.040 mol of solid NaOH is added to a 200.0 mL buffer containing 0.100 mol C6H5NH3Cl and 0.500 M C6H5NH₂. The value of Kb for C6H5NH₂ is 4.3 x 10-¹⁰. Use the table below to determine the moles of reactant and product after the reaction of the acid and base. You can ignore the amount of liquid water in the reaction. C6H5NH3(a OH-(aq) → H₂O(l) C6H5NH₂ (ac Before (mol) Change (mol) After (mol)