Question:

E Ag /Ag 2 Ag(s) + Fe²+ (aq) (1.0 M) = 2 Ag+ (aq) (1.0 M) +

Last updated: 8/5/2022

E Ag /Ag 2 Ag(s) + Fe²+ (aq) (1.0 M) = 2 Ag+ (aq) (1.0 M) +

E Ag /Ag 2 Ag(s) + Fe²+ (aq) (1.0 M) = 2 Ag+ (aq) (1.0 M) + Fe(s) K = = +0.80 V Eº Fe²/Fe = -0.44 V At 25°C, calculate the free energy change and the equilibrium constant of the reaction above. AG° = kJ/mol