Each step in the following process has a yield of 70.0%. CH4

Last updated: 8/4/2022

Each step in the following process has a yield of 70.0%. CH4 +4Cl₂→ CCI4 + 4HCI CCI + 2 HF→ CCI₂F₂ + 2HCl The CCI, formed in the first step is used as a reactant in the second step. If 8.00 mol CH₂ reacts, what is the total amount of HCI produced? Assume that Cl, and HF are present in excess. moles HCl: mol