EXAMPLE 5 Suppose that f 0 3 and f x 9 for all values of x

Last updated: 4/14/2024

EXAMPLE 5 Suppose that f 0 3 and f x 9 for all values of x How large can f 5 possibly be SOLUTION We are given that fis differentiable and therefore continuous everywhere In particular we can apply the Mean Value Theorem on the interval 0 5 There exists a number c such that f 5 f 0 f c 0 SO f 5 f 0 f c 3 f c We are given that f x s 9 for all x so in particular we know that f c s have 5f c s SO 7 f 5 3 f c 3 The largest possible value for f 5 is 29 Multiplying both sides of this inequality by 5 we