Question:
Factor completely: 2y³ + 8y² - 42y 2y (y² + 4y - 7) 2y(y +
Last updated: 7/16/2022

Factor completely: 2y³ + 8y² - 42y 2y (y² + 4y - 7) 2y(y + 7)(y - 3) 2y(y + 7)(y + 3) y(2y + 3) (3y + 7)
Last updated: 7/16/2022
Factor completely: 2y³ + 8y² - 42y 2y (y² + 4y - 7) 2y(y + 7)(y - 3) 2y(y + 7)(y + 3) y(2y + 3) (3y + 7)