Find an equation of the tangent line to the graph of the equation at the given point. (-2, 1) x² + x arctan y = y - 1, Step 1

Question

Find an equation of the tangent line to the graph of the equation at the given point.
(-2, 1)
x² + x arctan y = y - 1,
Step 1
Use implicit differentiation to find y'.
2x +
x² + x arctan y = y - 1,
+
X
1 + y²
-y' = y'
(₁ - 12) =
(1.
1+
y'

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