Question:

For the following reaction, 11.2 grams of glucose (C6H12O6)

Last updated: 8/3/2022

For the following reaction, 11.2 grams of glucose (C6H12O6)

For the following reaction, 11.2 grams of glucose (C6H12O6) are allowed to react with 15.7 grams of oxygen gas. glucose (C6H12O6)(s) + oxygen(g) → carbon dioxide(g) + water(l) What is the maximum amount of carbon dioxide that can be formed? What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete?