For the following reaction, 2.99 grams of methane (CHA) are

Last updated: 8/3/2022

For the following reaction, 2.99 grams of methane (CHA) are allowed to react with 32.4 grams of carbon tetrachloride. methane (CH4)(g) + carbon tetrachloride (g) ---> dichloromethane (CH₂Cl₂)(g) What is the maximum mass of dichloromethane (CH₂Cl₂) that can be formed? What is the FORMULA for the limiting reagent? What mass of the excess reagent remains after the reaction is complete?