For the following reaction, 56.3 grams of barium hydroxide

Last updated: 8/5/2022

For the following reaction, 56.3 grams of barium hydroxide are allowed to react with 30.3 grams of sulfuric acid. barium hydroxide (aq) + sulfuric acid(aq) --> barium sulfate(s) + water(l) What is the maximum amount of barium sulfate that can be formed? What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete?