For the following reaction, 6.26 grams of methane (CH4) are

Last updated: 7/29/2022

For the following reaction, 6.26 grams of methane (CH4) are allowed to react with 28.1 grams of carbon tetrachloride. methane (CH₂) (g) + carbon tetrachloride (g) dichloromethane (CH₂Cl₂) (g) What is the maximum amount of dichloromethane (CH₂Cl₂) that can be formed? What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams grams