For the functions f(x) = x² - x - 6 and g(x) = x - 3, (fg)(x) would be equal to: a) (fg)(x) = x + 2 b) (fg)(x) = x³ + 18 c)

Question

For the functions f(x) = x² - x - 6 and g(x) = x - 3, (fg)(x) would be equal to:
a) (fg)(x) = x + 2
b) (fg)(x) = x³ + 18
c) (fg)(x) = x³ − 4x² − 3x + 18
d) (fg)(x) = x² – 18

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