Question:
For what value of k will the function y = 3x²+4r-7/x²-5x+k
Last updated: 7/20/2022
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For what value of k will the function y = 3x²+4r-7/x²-5x+k have asymptotes at x = 6, x= -1, and y = 3? (A) k=6 (B) k=-6 (C) No such value of k exists because regardless of the horizontal asymptote is y = 0 (D) No such value of k exists because there will be a hole, not a vertical asymptote, at x= -1