Question:
Force between two identical charges placed at a distance r
Last updated: 6/9/2023

Force between two identical charges placed at a distance r in vacuum is F Now a slab of dielectric constant K 4 is inserted between these two charges The thickness of the slab is r 2 The force between the charges will now become a F 4 b F 2 c 3F 5 d 4F 9