From previous integration techniques we know that sec t dt In sec t tan t Use this to evaluate the trig integral from Part 1 and

Question

From previous integration techniques we know that sec t dt In sec t tan t Use this to evaluate the trig integral from Part 1 and then substitute back to get the final result in terms of To substitute back in terms of x you would use tan t sec t The final result of the integration would then be 2 2 16 d 15 dx C

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