gene HH and Hh hamsters have hair and hh hamsters are

Last updated: 8/24/2023

gene HH and Hh hamsters have hair and hh hamsters are hairless Multiple EeHh hamsters are mated together generating 400 progeny altogether Note that this is a different cross from the one discussed in Video 3 4 modeling use of Chi squared analysis to test for linkage here we have a cross between two dihybrids rather than a cross between a dihybrid and a tester Therefore the null hypothesis that E and H genes are unlinked will yield different expected values here compared to the testcross scenario when two dihybrids are crossed together and the genes are unlinked what proportion of each of the four progeny classes do we get Part 1 If the E and H genes are unlinked how many of the 400 progeny hamsters would you expect to be hairless and normal size 50 O 75 100 O225 150 Part 2 You perform the cross described above and get the results shown below Note that this problem uses a short hand convention you will want to get used to if a mutant phenotype is not mentioned assume it is absent Therefore assume that the progeny described below as hairless have normal body size Assume that the progeny described as dwarf have hair Hairless dwarf 33 Perform a chi square analysis for this cross testing the hypothesis that the E and H genes are unlinked using the chi square table below 1 Degrees of freedom 2 3 Wild type 212 Hairless 82 4 Dwarf 73 5 O 3 41 O 1 26 16 08 p 0 99 O 0 75 0 000157 0 020 0 115 0 297 0 554 0 95 0 00393 0 103 0 352 What is the total chi square value Round to two decimals 0 711 1 145 0 80 0 0642 0 446 1 005 1 649 2 343 0 50 0 455 1 386 2 366 3 357 4 351 0 20 1 642 3 219 4 642 5 989 7 289 0 05 3 841 5 991 7 815 9 488 11 070 0 01 6 635 9 210 11 345 13 277 15 086