Question:

Given: 4AICI3(s) + 302(g) Ⓡ 2Al2O3(s) + 6Cl2(g); DH = -529.0

Last updated: 8/6/2022

Given: 4AICI3(s) + 302(g) Ⓡ 2Al2O3(s) + 6Cl2(g); DH = -529.0

Given: 4AICI3(s) + 302(g) Ⓡ 2Al2O3(s) + 6Cl2(g); DH = -529.0 kJ determine DH for the following thermochemical equation. YOU MUST WRITE ALL CALCULATIONS OTHERWISE YOU WILL NO BE GRANTED FULL CREDIT Cl₂(g) + Al₂O3(s) ⓇAICI3(s) + O₂(g) +529.0 kJ -176.3 kJ +176.3 kJ +264.5 kJ +88.2 kJ