Question:
Given that 26x⁹ + 5x³⁹ y + y^8 dy/dx Now find an equation of
Last updated: 7/21/2022
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Given that 26x⁹ + 5x³⁹ y + y^8 dy/dx Now find an equation of the line tangent to the graph of 26x9 + 5x³9 y + y = 32 at (1, 1):
Last updated: 7/21/2022
Given that 26x⁹ + 5x³⁹ y + y^8 dy/dx Now find an equation of the line tangent to the graph of 26x9 + 5x³9 y + y = 32 at (1, 1):