Question:
Given the equation 4y²u𝓏𝓏 + 2(1-y²)u𝓏ᵧ - uᵧᵧ- 2y(2uₓ -
Last updated: 8/6/2022
![Given the equation 4y²u𝓏𝓏 + 2(1-y²)u𝓏ᵧ - uᵧᵧ- 2y(2uₓ -](https://media.kunduz.com/media/sug-question/raw/80432944-1659817520.9007595.jpeg?h=512)
Given the equation 4y²u𝓏𝓏 + 2(1-y²)u𝓏ᵧ - uᵧᵧ- 2y(2uₓ - uᵧ)/(1+ y²) = 0. Find the solution u(x, y) which satisfies u(x,0) = g(x) and uᵧ(x,0) = f(x), where f, g ∈ C²(R) are arbitrary functions.