Question:

H2CO3 ionizes as |H2CO3 = H+ + HCO3- K₁ = 4 x 10-6 HCO3

Last updated: 7/5/2022

H2CO3 ionizes as |H2CO3 = H+ + HCO3- K₁ = 4 x 10-6 HCO3

H2CO3 ionizes as |H2CO3 = H+ + HCO3- K₁ = 4 x 10-6 HCO3 = H+ + CO32- K2 = 5 x 10-11 The correct information (s) related with 0.5 M Na₂CO3 solution is/are (A) The degree of hydrolysis of Na₂CO3 is 0.02 (approx.) (B) The pH of solution is 2.0 (approx.) (C) pOH of solution is 2.0 (approx.) (D) [H₂CO3] = 2.5 × 10-⁹ (approx.)