Question:

I 0 5 g of fuming H SO4 oleum is diluted with water This

Last updated: 7/3/2023

I 0 5 g of fuming H SO4 oleum is diluted with water This

I 0 5 g of fuming H SO4 oleum is diluted with water This solution is completely neutralised by 26 7 mL of 0 4 N NaOH The percentage of free SO3 in the sample is 1 30 6 2 40 6 3 20 6 4 50 2 MnO 4HCl MnCl 2H O Ch the equivalent wt of HCI will be M Mol wt of HCl 1 M 2 M 2 3 2M 4 M 4 3 Number of moles of MnO 4 required to oxidise one mole of ferrous oxalate completely in acidic medium will be 1 0 6 mole 2 0 4 mole 3 7 5 moles 4 0 2 mole Bro Br 1 0652y Br 1 595 Then the species undergoing disproportionation is BrO 1 2 BrO 5 4 Consider the change in oxidation state of Bromine8 corresponding to different emf values as shown in the diagram below 1 82 V 1 5 V BrO Br 3 4 HBrO HBrO On the basis of the following E 0 values the strongest oxidizing agent is Fe CN Fe Fe e E 0 77 V 1 Fe CN 2 Fe 3 Fe 4 Fe CN 6 In the conversion H SO4 H S O8which process occurs Fe CN e E 0 35 V 1 Oxidation 2 Reduction 3 Oxidation as well as reduction 4 Neither oxidation nor reduction 7 In the reaction 2 Cut Cu Cu the equivalent weight of Cut is M is the mol wt of Cut 1 M M 2 4 1 3 4 2M Valency factor V for following redox reaction is respectively a As2 S AsO 0 b 1 1 10 c H3 PO PH3 H PO3 1 28 3 2 28 3 6 4 7 4 4 3 9 9 The oxidation number of phosphorus in Ba H PO 2 is 1 3 Page