Question:
If 8.7 moles of Al and 2.7 moles of Fe203 are allowed to
Last updated: 8/4/2022
If 8.7 moles of Al and 2.7 moles of Fe203 are allowed to react completely, how many moles of the excess reactant will remain? (Please give your answer with one decimal place even if one of the initial values does not show any decimal places.) 2AI + Fe2O3Al2O3 + 2Fe