If ƒ(x) = (3x − 4)² (6x² + 6)³ then: ƒ'(x) = [Suggestion:

Last updated: 7/20/2022

If ƒ(x) = (3x − 4)² (6x² + 6)³ then: ƒ'(x) = [Suggestion: use logarithmic differentiation.]