In a saturated solution of an ionic compound in water, there is an equilibrium between the solid compound and the dissolved

Question

In a saturated solution of an ionic compound in
water, there is an equilibrium between the solid
compound and the dissolved ions. The equilibrium
expression for this type of reaction is called the
solubility product constant, Ksp, which can be
calculated from the concentrations, in moles per
liter, of each ion in solution.
For example, the solubility reaction and solubility
product of barium carbonate, BaCO3, are
BaCO3(s) = Ba²+ (aq) + CO3²- (aq)
Ksp = [Ba2+][CO3²-]
Similarly, the solubility reaction and solubility
product of calcium sulfate, CaSO4, are
CaSO4(s) Ca²+ (aq) + SO4²- (aq)
Ksp = [Ca²+][SO4²-]
=
Part A
The solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What is the Ksp of barium
carbonate?
Express your answer numerically.
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Ksp =
Submit
Part B
VAE
μА
The solubility product constant of calcium sulfate, CaSO4, is 7.10 x 10-5. Its molar mass is 136.1 g/mol. How many
grams of calcium sulfate can dissolve in 40.5 L of pure water?
Express your answer to three significant figures and include the appropriate units.
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Value
Units
Review I Constants I Periodic Table
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Kunduz · Accepted Answer

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