Question:
In Gauss's theorem ∫E.ds=q/ε The surface integral is
Last updated: 7/10/2022
![In Gauss's theorem ∫E.ds=q/ε The surface integral is](https://media.kunduz.com/media/sug-question/raw/66330445-1657462301.4384658.jpeg?h=512)
In Gauss's theorem ∫E.ds=q/ε The surface integral is evaluated by choosing a closed surface called the Gaussian surface. Here (A) The closed surface can be of any shape or size (B) q is the net charge enclosed inside the Gaussian surface, charges outside the surface are not considered (C) E is the electric field due to all charges on the surface (D) The exact location of the charges inside the surface does not affect the value of the integral