In Gauss's theorem ∫E.ds=q/ε The surface integral is evaluated by choosing a closed surface called the Gaussian surface. Here

Question

In Gauss's theorem ∫E.ds=q/ε The surface integral is evaluated by choosing a closed surface called the Gaussian surface. Here
(A) The closed surface can be of any shape or size
(B) q is the net charge enclosed inside the Gaussian surface, charges outside the surface are not considered
(C) E is the electric field due to all charges on the surface
(D) The exact location of the charges inside the surface does not affect the value of the integral

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