Question:

In the combustion of methanol, 2CH3OH() + 30₂(g) → 2CO2(g)

Last updated: 7/31/2022

In the combustion of methanol, 2CH3OH() + 30₂(g) → 2CO2(g)

In the combustion of methanol, 2CH3OH() + 30₂(g) → 2CO2(g) + 4H₂O(g), How many moles of the excess reactant are left over if you react 0.335 moles of methanol with 0.268 moles of oxygen?