Question:

In the following reaction, how many mL of 0.350 M magnesium

Last updated: 7/31/2022

In the following reaction, how many mL of 0.350 M magnesium

In the following reaction, how many mL of 0.350 M magnesium bromide solution reacts with excess silver nitrate to form a 3.00 g of AgBr precipitate? (molar mass of AgBr = 187.77 g/mole) MgBr₂(aq) + 2AgNO3(aq) --> 2AgBr(s) + Mg(NO3)2(aq) 22.8 mL 45.6 mL 1.86 mL 91.3 mL none of these