In the reaction below, if 21.31 g of H2(g) reacts completely, then how many moles of ammonia (NH3) would form? (MW N₂ = 28.01

Question

In the reaction below, if 21.31 g of H2(g) reacts completely, then how many moles of
ammonia (NH3) would form? (MW N₂ = 28.01 g/mol; MW H₂ - 2.016 g/mol, MW NH₂ =
17.03 g/mol)
                                             N2(g) + 3 H2(g)⇒2 NH3(g)

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