Question:

Jared wanted to find three consecutive even integers whose

Last updated: 7/15/2022

Jared wanted to find three consecutive even integers whose

Jared wanted to find three consecutive even integers whose sum was 4 times the first of those integers. He let k represent the first integer, then wrote and solved this equation: k + (k+ 1) + (k + 2) = 4k. Did he get the correct answer? Complete the explanation. Jared did not get the correct answer. The solution to his equation is k= giving and 3 and 5 are not even integers. He should have used the equation k+ (k+ ) + (k+ )=4k, which gives k = answer as the three integers. However, and the correct